← All courses  ›  Calculus Refresher  ›  Limits  ›  Introduction (Pretest)  ›  Q5

Limits · Pretest Q5

One-sided limits, jump discontinuities, and the missing half of the continuity story

Question 5 (1 pt)

The graph of $f(x)$ is shown below. Use it to evaluate $\displaystyle\lim_{x \to 3^-} f(x)$.

Graph of f(x) showing a piecewise function: a line segment on the left ending at a closed dot at (3, 2), and a downward parabola on the right starting at an open circle at (3, 4), peaking around (4, 5), and descending through the x-axis near x = 6

1 · The intuition

Intuition

The little $\boldsymbol{-}$ superscript on $\to 3^-$ is the key symbol here. It means "approach 3 from the left side only" — i.e., $x$ values like $2.9$, $2.99$, $2.999$, getting closer to $3$ but staying strictly less than $3$.

The little $\boldsymbol{+}$ (which you'll see in the next problem) means "from the right."

One-sided limits matter because a function can behave differently on the left of a point than on the right. In Q4, the function matched on both sides; in Q5, the two sides disagree at $x=3$. The notation lets you ask about each side separately.

2 · Notation

Notation — the three flavors of "limit at a point"

For a function $f$ and a point $x = a$:

Notation Name What you're asking
$\displaystyle\lim_{x \to a^-} f(x)$ Left-hand limit What does $f$ approach as $x$ gets close to $a$ from below (from the left)?
$\displaystyle\lim_{x \to a^+} f(x)$ Right-hand limit What does $f$ approach as $x$ gets close to $a$ from above (from the right)?
$\displaystyle\lim_{x \to a} f(x)$ Two-sided limit Both one-sided limits exist and equal the same value.

The two-sided limit exists if and only if both one-sided limits exist and agree:

$$\lim_{x \to a} f(x) = L \quad \iff \quad \lim_{x \to a^-} f(x) = L \;\text{ and }\; \lim_{x \to a^+} f(x) = L$$

3 · Worked solution

Worked solution

For $\displaystyle\lim_{x \to 3^-} f(x)$ in the graph above:

Step 1 — Identify which piece of the function matters.

The "from the left" means we ignore everything to the right of $x = 3$. So we look at the linear piece that ends at the closed dot at $(3, 2)$.

Step 2 — Trace the linear piece toward $x = 3$.

The line has equation $y = \dfrac{2}{3}x$ (slope $\tfrac{2}{3}$, passes through $(-1, 0)$). As $x \to 3^-$:

$$f(x) \to \frac{2}{3}(3) = 2$$

The line approaches the closed dot at $(3, 2)$. So the left-hand limit is $2$.

Step 3 — Note: the open circle does NOT matter for this question.

The open circle at $(3, 4)$ is on the right side of $x = 3$. It would matter for $\lim_{x \to 3^+} f(x)$, but not for the left-hand limit. The closed dot is what we approach from the left.

$\displaystyle\lim_{x \to 3^-} f(x) = 2$

4 · What about the right-hand limit? (bonus, not asked)

Bonus

For the same function, the right-hand limit $\lim_{x \to 3^+} f(x)$ would be 4 — the curve approaches the open circle from the right.

So the two one-sided limits disagree:

$$\lim_{x \to 3^-} f(x) = 2 \quad \neq \quad 4 = \lim_{x \to 3^+} f(x)$$

Which means the two-sided limit $\lim_{x \to 3} f(x)$ does not exist. The function "jumps" from $y = 2$ to $y = 4$ at $x = 3$.

5 · Connection to Q4 — the jump discontinuity

The continuity thread continues

Compare Q4 and Q5 in terms of the 3-condition continuity test:

Condition Q4 at $x = 3$ Q5 at $x = 3$
1. $f(3)$ is defined ✓ Yes ($= 2$) ✓ Yes ($= 2$)
2. $\lim_{x \to 3} f(x)$ exists ✓ Yes ($= 5$) No — left = 2, right = 4
3. $f(3) = \lim f(x)$ ✗ (different values) ✗ (limit doesn't exist)
Type of discontinuity Removable (cond 3 fails) Jump (cond 2 fails)

Q5 is the textbook example of a jump discontinuity: both one-sided limits exist (they're finite numbers), but they don't agree. There's a literal jump in the graph — your pen has to leave the page and reconnect at a different height.

6 · Common traps

Watch out
  1. Confusing the closed dot with the open circle. The closed dot at $(3, 2)$ is what the left-hand limit approaches. The open circle at $(3, 4)$ is what the right-hand limit approaches. If you wrote $4$, you read the right side by accident.
  2. Reading "from the left" as "the left side of the graph". The whole question is just about what $f(x)$ does as $x$ approaches $3$ from below. The left side of the page is just where the linear piece happens to live — the direction of approach is what matters.
  3. Writing the function value $f(3) = 2$ instead of the limit. In this problem they happen to be the same number, but they're different concepts. $f(3)$ is a specific y-value; the limit is what the curve approaches. On a removable discontinuity (Q4) they'd differ; on a step function (like the floor function) they often differ too.
  4. Reporting the answer with the wrong sign of the limit direction. If the question asked for $\lim_{x \to 3^+}$ and you wrote $2$, you'd get the same numerical penalty even though you understood the concept — just wrong side. Slow down and match the symbol.

7 · Check your understanding

Practice

For the same graph above, answer these:

  1. $\displaystyle\lim_{x \to 3^+} f(x) = ?$
  2. $\displaystyle\lim_{x \to 3} f(x) = ?$ (two-sided)
  3. What is $f(3)$?
  4. Is $f$ continuous at $x = 3$? Which condition of the continuity test fails?
  5. What kind of discontinuity is this? (removable / jump / infinite)
Show answers
  1. $4$ — the curve approaches the open circle from the right.
  2. DNE — left and right one-sided limits are unequal ($2 \neq 4$), so the two-sided limit doesn't exist.
  3. $2$ — read from the closed dot at $(3, 2)$.
  4. No. Condition 2 fails: the two-sided limit doesn't exist.
  5. Jump discontinuity — both one-sided limits exist and are finite, but they differ.

8 · What's next

One-sided limits are the engine behind the rigorous $\varepsilon$-$\delta$ definition of a limit. They're also the key tool for two big results you'll meet next:

Send the next pretest problem, or tell me which technique to drill next.

← Q4: Continuity & discontinuity Q6: Derivatives, power rule → ← All Introduction (Pretest) questions
Lesson built by Aida for TK · Notre Dame MSDS