Same function as Q1 — but stop one step earlier. Reading the question's exact wording matters.
The phrase "general difference quotient" means the secant-slope formula before you take the limit. Q1 asked for the tangent slope (the limit), Q2 asks for the secant slope (the limit's input). Same first four steps of the 5-step dance; the limit never happens.
Two ways to know you've got the right answer:
The general difference quotient (a.k.a. secant slope, a.k.a. average rate of change) is:
$$\frac{f(x+h) - f(x)}{h}$$Three names, one object. The word "general" just means "valid for any $x$" (as opposed to a specific pair of points like $x = 1$ and $x = 3$). The word "quotient" is the giveaway: numerator divided by denominator.
Given $f(x) = 2x^2 + 1$. Same expansion as Q1, but we stop after step 4.
Step 1 — Write the difference quotient.
$$\frac{f(x+h) - f(x)}{h}$$Step 2 — Compute $f(x+h)$.
$$f(x+h) \;=\; 2(x+h)^2 + 1 \;=\; 2x^2 + 4xh + 2h^2 + 1$$Step 3 — Subtract $f(x) = 2x^2 + 1$.
$$f(x+h) - f(x) \;=\; (2x^2 + 4xh + 2h^2 + 1) - (2x^2 + 1) \;=\; 4xh + 2h^2$$Step 4 — Divide by $h$ and simplify.
$$\frac{4xh + 2h^2}{h} \;=\; \frac{h(4x + 2h)}{h} \;=\; 4x + 2h$$No step 5. The question says "difference quotient" — that's the formula before the limit. We stop here.
Final answer:
Three phrases that look similar but mean different things — sorted by how much work you've done:
| Difference quotient | $\dfrac{f(x+h) - f(x)}{h}$ | secant slope, still has $h$ |
| Derivative | $\displaystyle\lim_{h \to 0} \dfrac{f(x+h) - f(x)}{h}$ | tangent slope, $h$ is gone |
| "Simplify" | $\dfrac{4xh + 2h^2}{h} \to 4x + 2h$ | the one allowed $h$ cancel |
So: "difference quotient" = stop at step 4. "Derivative" or "tangent slope" or "limit" = go all the way to step 5. Watch the verb.
Find and simplify the general difference quotient of $g(x) = x^2 + 3x$.
Hint: this has two terms in $g(x)$, so when you compute $g(x+h)$ you'll have two expansions. Subtract carefully.
Step 2: $g(x+h) = (x+h)^2 + 3(x+h) = x^2 + 2xh + h^2 + 3x + 3h$
Step 3: $g(x+h) - g(x) = (x^2 + 2xh + h^2 + 3x + 3h) - (x^2 + 3x) = 2xh + h^2 + 3h$
Step 4: $\dfrac{2xh + h^2 + 3h}{h} = \dfrac{h(2x + h + 3)}{h} = 2x + h + 3$
Sanity check: the difference quotient is a function of two variables ($x$ and $h$). Three terms, $h$ in two of them — that's what the secant slope should look like.
Send Q3 whenever you have it. The 5-step pattern holds — just watch the wording (difference quotient vs. derivative vs. tangent slope) to know where to stop.